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Question

X is a Normally distributed variable with mean =30 and standard deviation =4. Find P(x<40)

A
0.9789
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B
0.9938
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C
0.9838
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D
0.9538
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Solution

The correct option is A 0.9938
P(x<40)=P(Z<(4030)/4)=P(Z<2.5)=0.9938
The value 0.9938 is taken from normal distribution table.

746977_701390_ans_340441d7c6f54571b7a4be632623f355.png

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