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Standard XII

Mathematics

Standard Deviation about Mean for Continuous Frequency Distributions

X is a Normal...

Question

$X$ is a Normally distributed variable with mean $= 30$ and standard deviation $= 4$ . Find $P (x < 40)$

0.9789

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0.9938

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0.9838

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0.9538

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Solution

The correct option is A $0.9938$
$P (x < 40) = P (Z < (40 - 30) / 4) = P (Z < 2.5) = 0.9938$
The value $0.9938$ is taken from normal distribution table.

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X is a Normally distributed variable with mean =30 and standard deviation =4. Find P(x<40)

The correct option is A 0.9938P(x<40)=P(Z<(40−30)/4)=P(Z<2.5)=0.9938The value 0.9938 is taken from normal distribution table.

$X$ is a Normally distributed variable with mean $= 30$ and standard deviation $= 4$ . Find $P (x < 40)$

The correct option is A $0.9938$
$P (x < 40) = P (Z < (40 - 30) / 4) = P (Z < 2.5) = 0.9938$
The value $0.9938$ is taken from normal distribution table.