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Standard XII

Chemistry

Non-Ideal Solutions

X is a Normal...

Question

$X$ is a Normally distributed variable with mean $= 30$ and standard deviation $= 4$ . Find $P (x > 21$ )

0.9878

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0.9383

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0.9975

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0.9126

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Solution

The correct option is A $0.9878$
$P (x > 21) = P (Z > (21 - 30) / 4) = P (Z > - 2.25) = 0.9878$
The value $0.9878$ is taken from table.

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X is a Normally distributed variable with mean =30 and standard deviation =4. Find P(x>21)

The correct option is A 0.9878P(x>21)=P(Z>(21−30)/4)=P(Z>−2.25)=0.9878The value 0.9878 is taken from table.

$X$ is a Normally distributed variable with mean $= 30$ and standard deviation $= 4$ . Find $P (x > 21$ )

The correct option is A $0.9878$
$P (x > 21) = P (Z > (21 - 30) / 4) = P (Z > - 2.25) = 0.9878$
The value $0.9878$ is taken from table.