X is a point in the interior of △ DEF joined to its vertices D, E and F. From a point P on DX, PQ is drawn parallel to DE, meeting XE at Q. QR is drawn parallel to EF meeting XF at R. Which of the following is correct?
A
PQ ∥ DF
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B
QR ∥ DF
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C
PR ∥ DF
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D
PQ ∥ QR
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Solution
The correct option is C PR ∥ DF As can be seen from the figure, using the information given in the passage
If PQ||ED, => implies that XPPD=XQEQ
If QR||EF,=> implies that XQQE=XRRF
Using both the equations, we can say that XPPD=XRRF