Question

$x$ is six times as large as $y$. By what percent is $y$ less than $x$?

• A. $83.33\%$
• B. $16.66\%$
• C. $90\%$
• D. $60\%$

Answer 1

The correct option is A $83.33\%$

It is given that $x$ is 6 times larger than $y$.

$x=6y$

Percent of $y$ is less than $x=\frac{x-y}{x}\times 100$

$=\frac{6y-y}{6y}\times 100$

$=\frac{5}{6}\times 100$

$=83.33\%$

Hence, $y$ is $83.33\%$ less than $x.$