Question

X is treated with $LiAi{H}_4$ to obtain compound $Y\left(C_2{H}_{7}N\right)$. In separate reaction X is hydrolyzed in an acid medium to obtain Z.The product obtained after mixing Y and will be:

• A. ${CH}_{3}CONHC{H}_2{CH}_3$
• B. ${CH}_3{CH}_{2}CONHC{H}_2{CH}_3$
• C. $\left({CH}_3{COO}^{-}\right)\left({CH}_3{CH}_2{N}_3^{+}\right)$
• D. $\left({CH}_3{CH}_2{COO}^{-}\right)\left({CH}_3{N}_2^{+}\right)$

Answer 1

The correct option is A ${CH}_{3}CONHC{H}_2{CH}_3$

$X\underset{LiAl{H}_4}{\overset{}{\to }}Y\left(C_2{H}_{7}N\right)$

$X\underset{Acidic}{\overset{Medium}{\to }}Y$

In the above reaction, $LiAl{H}_4$ is used which acts as a reducing agent in organic synthesis, especially for reduction esters, carboxylic acids and amides. It is also said to reduce alkyl halides to alkanes.

The final product which is formed is a amide derivative.