Question

X lies in the interior of $\angle BAC$. If $\angle BAC={70}^o$ and $\angle BAX={42}^o$ then $\angle XAC:$

• A. ${28}^o$
• B. ${29}^o$
• C. ${27}^o$
• D. ${30}^o$

Answer 1

Answer: (A)

${28}^o$

$\angle BAC={70}^{\circ }$, $\angle BAX={42}^{\circ }$
Now,
$\angle BAC=\angle BAX+\angle XAC$
$70=42+\angle XAC$
$\angle XAC={28}^{\circ }$.