′X′ litres of carbon monoxide is present at STP. It is completely oxidized to CO2. The volume of CO2 formed is 11.207 litres at STP. What is the value of ′X′ in litres?
A
22.414
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B
11.207
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C
5.6035
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D
44.828
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Solution
The correct option is B11.207 CO+12O2→CO2 The complete oxidation of 1 mol (22.4 L) of CO gives 1 mol (22.4 L) of CO2. Thus, 11.207 L of CO2 will be produced by complete combustion of 11.207×22.422.4=11.207L of CO.