Question

'$x$' moles of $N_2$ gas at $S.T.P$ conditions occupy a volume of $10$ lit then the volume of '$2x$' moles of $C{H}_4$ at $273$${}^{\circ }C$ and $1.5atm$ is?

• A. $20$ lit
• B. $26.6$ lit
• C. $5$ lit
• D. $16.6$ lit

Answer 1

Answer: (B)

$26.6$ lit

Consider the given value,

$n=x$

$P=1.5atm$

$V=10lit$

$T={273}^{\circ }C$

$R=?$

$S.T.P=1atmat{0}^{\circ }C$

$PV=nRT$

$1\times 10=x\times R\times 273$

$10=x\times R\times 273$

$R=\frac{10}{(x\times 273)}$

If you meant $273K$

Therefore,

$\left(\frac{3}{2}\right)\times V=2x\times (273+273)\times \frac{10}{\left(273x\right)}$

$\left(\frac{3}{2}\right)\times V=20\times 2$

$V=40\times \left(\frac{2}{3}\right)$

$V=\frac{80}{3}$

$V=26.6Liters$