If one mole of a gas (mol.wt-40) occupies a volume of 20 litres, under the same conditions of temperature and pressure the volume occupied by 2 moles of gas (mol.wt=80) is

Q. Assertion :8 grams of methane occupies 11.2 litres of volume at 273

K

and 1

a t m

pressure. Reason: One mole of any gas at

S T P

occupies 22.4 litres of volume.

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'x' moles of N2 gas at S.T.P conditions occupy a volume of 10 litres, then the volume of '2x' moles of CH4 at 2730 C and 1.5 atm is

The correct option is B 26.6 lit P1V1n1T1=P2V2n2T2 1×10n×273=1.5×V22x×546 V2=26.6 lit

'x' moles of $N_{2}$ gas at S.T.P conditions occupy a volume of 10 litres, then the volume of '2x' moles of $C H_{4}$ at $273^{0} C$ and 1.5 atm is

The correct option is B
26.6 lit

$\frac{P_{1} V_{1}}{n_{1} T_{1}} = \frac{P_{2} V_{2}}{n_{2} T_{2}}$

$\frac{1 \times 10}{n \times 273} = \frac{1.5 \times V_{2}}{2 x \times 546}$

$V_{2} = 26.6 l i t$