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Question

xnyn is divisible by x+y, when:

A
n is rational
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B
n is an positive integer
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C
n is an even positive integer
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D
n is an odd
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Solution

The correct option is D n is an even positive integer
Let,
f(x)=xnyn and
g(x)=x+y
=>x+y=0
=>x=y
If f(x) is divided by g(x) then,f(y) should be equal to zero.
Therefore,
f(y)=(y)nyn
=0 if n is even
0 if n is odd
Therefore,
x+y is a factor of xnyn when n is a even integer.

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