X number of electrons would have about the same mass as proton or a neutron? Identify X.

200

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500

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2000

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5000

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Solution

The correct option is D 2000
$e l e c t r o n m a s s = {9.1 \times 10}^{- 31} k g p r o t o n m a s s = {1.67 \times 10}^{- 27} k g F o r 2000 e = {9.1 \times 10}^{- 31} \times 2000 = {1.82 \times 10}^{- 27} k g ≃ {1.67 \times 10}^{- 27} k g$

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Similar questions

Q. Identify the correct statements.
(i) Atomic number = number of protons + number of electrons
(ii) Mass number = number of protons + number of neutrons
(iii) Atomic mass = number of protons = number of neutrons
(iv) Atomic number = number of protons = number of electrons

Question 07

Two atoms are said to be isobars if ?

(a) They have same atomic number but different mass number

(b) They have same number of electrons but different number of neutrons

(d) Sum of the number of protons and neutrons is same but the number of protons is different

Q. An element is represented by

_{Z} X^{A}

, where Z is atomic number which is also equal to number of proton, A is mass number and X is symbol of the element.
Mass number (A) = Number of protons (Z) + Number of neutrons.
Isotopes: Atoms having same number of proton
Isobar: Elements having same mass number
Isotones: Elements having same number of neutron (A-Z)

The sum of the number of electrons, protons and neutrons in the three isotopes

(^{16} O,^{17} O,^{18} O)

of oxygen is:

Q. The isotopes of an element contain :

(a) same number of neutrons but different number of protons

(b) same number of neutrons but different number of electrons

(d) different number of neutrons but same number of protons

Which of the following statements is/ are correct about neutral elements?

(i) Atomic number = number of protons = number of electrons
(ii) Mass number = number of protons + number of neutrons
(iii) Atomic number = number of protons + number of electrons
(iv) Mass number = number of neutrons = number of electrons

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X number of electrons would have about the same mass as proton or a neutron? Identify X.

The correct option is D 2000electronmass=9.1×10−31kgprotonmass=1.67×10−27kgFor2000e=9.1×10−31×2000=1.82×10−27kg≃1.67×10−27kg

The correct option is D 2000
$e l e c t r o n m a s s = {9.1 \times 10}^{- 31} k g p r o t o n m a s s = {1.67 \times 10}^{- 27} k g F o r 2000 e = {9.1 \times 10}^{- 31} \times 2000 = {1.82 \times 10}^{- 27} k g ≃ {1.67 \times 10}^{- 27} k g$