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Byju's Answer
Standard XII
Chemistry
Liquefaction of Gases and Critical Constants
xLt→0[∫0xcos ...
Question
x
L
t
→
0
[
∫
x
0
cos
t
2
d
t
x
]
=
A
0
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B
1
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C
−
1
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D
2
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Solution
The correct option is
A
1
x
L
t
→
0
[
∫
x
0
c
o
s
t
2
d
t
x
]
0
0
f
o
r
m
So,
=
x
L
t
→
0
c
o
s
x
2
1
=
1
Suggest Corrections
0
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Q.
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→
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+
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t
=
Q.
x
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[
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t
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Q.
The equations of the tangents drawn from the point (0, 1) to the circle
x
2
+
y
2
−
2
x
+
4
y
=
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are
Q.
Find the values of k for which the roots are real and equal in each of the following equations:
(i)
k
x
2
+
4
x
+
1
=
0
(ii)
k
x
2
-
2
5
x
+
4
=
0
(iii)
3
x
2
-
5
x
+
2
k
=
0
(iv)
4
x
2
+
k
x
+
9
=
0
(v)
2
k
x
2
-
40
x
+
25
=
0
(vi)
9
x
2
-
24
x
+
k
=
0
(vii)
4
x
2
-
3
k
x
+
1
=
0
(viii)
x
2
-
2
5
+
2
k
x
+
3
7
+
10
k
=
0
(ix)
3
k
+
1
x
2
+
2
k
+
1
x
+
k
=
0
(x)
k
x
2
+
k
x
+
1
=
-
4
x
2
-
x
(xi)
k
+
1
x
2
+
2
k
+
3
x
+
k
+
8
=
0
(xii)
x
2
-
2
k
x
+
7
k
-
12
=
0
(xiii)
k
+
1
x
2
-
2
3
k
+
1
x
+
8
k
+
1
=
0
(xiv)
2
k
+
1
x
2
+
2
k
+
3
x
+
k
+
5
=
0
(xvii)
4
x
2
-
2
k
+
1
x
+
k
+
4
=
0
(xviii)
x
2
-
2
k
+
1
x
+
k
2
=
0
(xix)
k
2
x
2
-
2
2
k
-
1
x
+
4
=
0
(xx)
k
+
1
x
2
-
2
k
-
1
x
+
1
=
0
(xxi)
2
x
2
+
k
x
+
3
=
0
(xxii)
k
x
x
-
2
+
6
=
0
(xxiii)
x
2
-
4
k
x
+
k
=
0
(xxiv)
k
x
x
-
2
5
+
10
=
0
(xxv)
p
x
(
x
-
3
)
+
9
=
0
(xxvi)
4
x
2
+
p
x
+
3
=
0