Question

X-Rays of shortest wavelength of 0.02 nm are produced, when an X-Ray tube operates at a potential difference of

• A. 62 KV
• B. 124 KV
• C. 248 KV
• D. 100 KV

Answer 1

The correct option is A 62 KV

$Energy=\frac{hc}{\lambda }$

=$\frac{1240}{0.02}$

=62,000 eV
energy = $p.d\times e$

$p.d=\frac{energy}{e}$

=$\frac{62,000eV}{e}$

=$62\times {10}^{3}V$
=62 KV

So, the answer is option (A).