X- rays of wavelength equal to 0-134 nm give a first order diffraction from the surface of a crystal when the value of - is 10-5- - Calculate the distance between the planes in the crystal parallel to the surface examined-

Given λ =0.134 nm, θ =10.5^∘ n = 1 Applying Bragg’s equation 2d Sin θ = n λ d = nλ/2Sin θ=1 ×0.134/2× Sin 10.5^∘ = 0.134/2× 0.1822 = 3.68 A ...

You visited us 6 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

First Order Reaction

X- rays of wa...

Question

X- rays of wavelength equal to 0.134 nm give a first order diffraction from the surface of a crystal when the value of $θ$ is ${10.5}^{\circ}$ . Calculate the distance between the planes in the crystal parallel to the surface examined.

Open in App

Solution

Given $λ = 0.134 n m, θ = {10.5}^{\circ}$
n = 1
Applying Bragg’s equation
$2 d S i n θ = n λ$
$d = \frac{n λ}{2 S i n θ} = 1 \times \frac{0.134}{2} \times S i n {10.5}^{\circ} = \frac{0.134}{2} \times 0.1822 = 3.68 A$

Suggest Corrections

Similar questions

Q. The diffraction of a crystal of Barium with X-rays of wavelength 2.29angstroms gives a first order reflection at

{27.8}^{\circ}

. What is the distance between the diffracting planes (In angstroms)? (Sin 27.8 = 0.4561)

Q. What will be the wavelength of the X-rays which give a diffraction angle

2 θ

equal to

{16.80}^{o}

for a crystal, if the inter planner distance in the crystal is 0.200 nm and only first order diffraction is observed

(sin {8.40}^{o} = 0.146) .

Q. The first order diffraction of X- rays from a certain set of crystal planes occurs at an angle of

{11.8}^{o}

from the planes. If the planes are 0.281 nm apart, the wavelength of x-rays is

(s i n {11.8}^{o} = 0.2045)

The second order Bragg diffraction of x-rays with $λ = 1.00 \circ A$ from a set of parallel planes in metal occurs at an angle $60^{\circ}$ . The distance between the scattering planes in the crystal is

Q. The second order Bragg's diffraction of rays with

λ

= 1A from a set of parallel planes in a metal occurs at an angle of

60^{\circ}

The distance between the scattering planes in the crystal is

Join BYJU'S Learning Program

X- rays of wavelength equal to 0.134 nm give a first order diffraction from the surface of a crystal when the value of θ is 10.5∘. Calculate the distance between the planes in the crystal parallel to the surface examined.

Given λ=0.134nm,θ=10.5∘ n = 1 Applying Bragg’s equation 2d Sin θ=n λ d=nλ2Sinθ=1×0.1342×Sin10.5∘=0.1342×0.1822=3.68A

X- rays of wavelength equal to 0.134 nm give a first order diffraction from the surface of a crystal when the value of $θ$ is ${10.5}^{\circ}$ . Calculate the distance between the planes in the crystal parallel to the surface examined.

Given $λ = 0.134 n m, θ = {10.5}^{\circ}$
n = 1
Applying Bragg’s equation
$2 d S i n θ = n λ$
$d = \frac{n λ}{2 S i n θ} = 1 \times \frac{0.134}{2} \times S i n {10.5}^{\circ} = \frac{0.134}{2} \times 0.1822 = 3.68 A$