X- rays of wavelength equal to 0-134 nm give a first order diffraction from the surface of a crystal when the value of - is 10-5- - Calculate the distance between the planes in the crystal parallel to the surface examined-

Given λ =0.134 nm, θ =10.5^∘ n = 1 Applying Bragg’s equation 2d Sin θ = n λ d = nλ/2Sin θ=1 ×0.134/2× Sin 10.5^∘ = 0.134/2× 0.1822 = 3.68 A ...

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Standard XII

Chemistry

First Order Reaction

X- rays of wa...

Question

X- rays of wavelength equal to 0.134 nm give a first order diffraction from the surface of a crystal when the value of $θ$ is ${10.5}^{\circ}$ . Calculate the distance between the planes in the crystal parallel to the surface examined.

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Solution

Given $λ = 0.134 n m, θ = {10.5}^{\circ}$
n = 1
Applying Bragg’s equation
$2 d S i n θ = n λ$
$d = \frac{n λ}{2 S i n θ} = 1 \times \frac{0.134}{2} \times S i n {10.5}^{\circ} = \frac{0.134}{2} \times 0.1822 = 3.68 A$

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X- rays of wavelength equal to 0.134 nm give a first order diffraction from the surface of a crystal when the value of θ is 10.5∘. Calculate the distance between the planes in the crystal parallel to the surface examined.

Given λ=0.134nm,θ=10.5∘ n = 1 Applying Bragg’s equation 2d Sin θ=n λ d=nλ2Sinθ=1×0.1342×Sin10.5∘=0.1342×0.1822=3.68A

X- rays of wavelength equal to 0.134 nm give a first order diffraction from the surface of a crystal when the value of $θ$ is ${10.5}^{\circ}$ . Calculate the distance between the planes in the crystal parallel to the surface examined.

Given $λ = 0.134 n m, θ = {10.5}^{\circ}$
n = 1
Applying Bragg’s equation
$2 d S i n θ = n λ$
$d = \frac{n λ}{2 S i n θ} = 1 \times \frac{0.134}{2} \times S i n {10.5}^{\circ} = \frac{0.134}{2} \times 0.1822 = 3.68 A$