X-rays of wavelength $λ$ are incident normally on a crystal and the second order reflection of diffraction from the crystal is observed at an angle of $45^{\circ}$ . The lattice constant of the crystal is

$\frac{λ}{\sqrt{2}}$

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$\sqrt{2} λ$

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$λ$

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$2 λ$

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Solution

The correct option is B
$\sqrt{2} λ$

Here, order $n = 2$ and $θ = 45^{\circ}$
From Bragg's equation, $2 d s i n 45^{\circ} = 2 λ \Rightarrow d = \sqrt{2} λ$
Hence, the correct choice is (b).

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X-rays of wavelength λ are incident normally on a crystal and the second order reflection of diffraction from the crystal is observed at an angle of 45∘. The lattice constant of the crystal is

The correct option is B √2λ Here, order n=2 and θ=45∘ From Bragg's equation, 2d sin 45∘=2λ⇒d=√2 λ Hence, the correct choice is (b).

X-rays of wavelength $λ$ are incident normally on a crystal and the second order reflection of diffraction from the crystal is observed at an angle of $45^{\circ}$ . The lattice constant of the crystal is

The correct option is B
$\sqrt{2} λ$

Here, order $n = 2$ and $θ = 45^{\circ}$
From Bragg's equation, $2 d s i n 45^{\circ} = 2 λ \Rightarrow d = \sqrt{2} λ$
Hence, the correct choice is (b).