Question

X rays wavelength $22$ pm are scattered from a carbon. find $\lambda$:

• A. $28.2pm$
• B. $26.2pm$
• C. $24.2pm$
• D. $27.2pm$

Answer 1

Answer: (C)

$24.2pm$

$\Delta \lambda =\frac{h}{mc}(1-cos\theta )$

$\Delta \lambda =\frac{6.626\times {10}^{-34}}{9.1\times {10}^{-31}\times 3\times {10}^8}(1-0.088)$

$\Delta \lambda =\lambda -{\lambda }^{/}=2.42\times {10}^{-12}\times \left(0.912\right)$

${\lambda }^{/}=\lambda +2.20\times {10}^{-12}$

${\lambda }^{/}=(22+2.20)pm$

=24.2pm