Question

$X\to Y$ is a second order reaction. If concentration of $X$ is increased by three times, how will it affact the rate of formation of $Y$?

Answer 1

$X\to Y$ is a Second order reaction.

$rate=k[X{]}^2$

If the concentration of X is increased by $3$ times, then the rate of formation of Y becomes $3^2$ = 9 times