Question

Factorize: $\frac{x^3+1}{x^3-1}$

Answer 1

Given: $\frac{x^3+1}{x^3-1}$

$=\frac{(x+1)(x^2-x+1)}{(x-1)(x^2+x+1)}$

Hence, $\frac{x^3+1}{x^3-1}=\frac{(x+1)(x^2-x+1)}{(x-1)(x^2+x+1)}$