$x - t$ graph of a particle undergoing SHM is shown. Acceleration of particle at $t = 4 / 3 s$ is

\sqrt{3} π^{2} m / s^{2}

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π^{2} m / s^{2}

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\frac{- π^{2}}{4} m / s^{2}

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- \sqrt{3} π^{2} m / s^{2}

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Solution

The correct option is D $- \sqrt{3} π^{2} m / s^{2}$
$x = - A s i n ω t$
$v = - A ω c o s ω t$
& $a = A ω^{2} s i n ω t$

$∵ T = 2 s$
$∴ ω = \frac{2 π}{T} = π$
& $A = 2 m$

$∴ a$ at
$t = \frac{4}{3} s = 2 π^{2} s i n \frac{4 π}{3} m / s^{2} = - \sqrt{3} π^{2} m / s^{2}$

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x−t graph of a particle undergoing SHM is shown. Acceleration of particle at t=4/3 s is

The correct option is D −√3π2 m/s2 x=−A sinωt v=−Aω cosωt & a=Aω2 sinωt ∵T=2 s ∴ω=2πT=π & A=2 m ∴a at t=43s=2π2 sin4π3 m/s2=−√3π2 m/s2

$x - t$ graph of a particle undergoing SHM is shown. Acceleration of particle at $t = 4 / 3 s$ is

The correct option is D $- \sqrt{3} π^{2} m / s^{2}$
$x = - A s i n ω t$
$v = - A ω c o s ω t$
& $a = A ω^{2} s i n ω t$

$∵ T = 2 s$
$∴ ω = \frac{2 π}{T} = π$
& $A = 2 m$

$∴ a$ at
$t = \frac{4}{3} s = 2 π^{2} s i n \frac{4 π}{3} m / s^{2} = - \sqrt{3} π^{2} m / s^{2}$