X varies directly as the square of Y. If X = 1 when Y = 2, then find the constant of variation.
A
0.25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.75
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A 0.25 Let the constant of variation be k. Given, X varies directly as as the square of Y. ⇒X∝Y2 ⇒X=kY2 Given, at X = 1, Y = 2. So, k=XY2=122=14=0.25