x∝y and x∝1z. if y = 5, z = 4 , then x = 3. Now, if y = 30 and z = 16 ,then x =
9/2
x∝y and x∝1z
⇒ x ∝ yz
⇒ x = k.(yz)
Putting the given values of x, y and z we get :
3=k.(54)
⇒ k = 125
Now , putting the new value of k along with y and z we get :
x = (125)×(3016)=92