CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

X=x210123
P(X=x)0.1K0.22K0.3K
is the probability distribution of random variable X. Find the value of K and variance of X.

Open in App
Solution

P(X=x)=10.1+k+0.2+2k+0.3+k=1k=0.1
Therefore,
X=x210123
P(X=x)0.10.10.20.20.30.1
Variance (X)=(xμ)2P(X=x)
μ=2×0.1+(1)(0.1)+0(0.2)+1(0.2)+2(0.3)+3(0.1)μ=0.8
Therefore,
Var(X)=(20.8)2(0.1)+(10.8)2(0.1)+(00.8)2(0.2)+(10.8)2(0.2)+(20.8)2(0.3)+(30.8)2(0.1)=2.05

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Probability Distribution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon