X−−−−−→(AgNO3)Y (white ppt.) Y is soluble in nitric acid and ammonia. The ppt. becomes yellowish brown upon addition of excess reagent owing to the formation of Z. If aqueous suspension of Y is boiled then it gives same product Z.
Here Z is:
A
Ag2CO3
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B
Ag
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C
Ag2O
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D
All of these
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Solution
The correct option is CAg2O CO2−3−−−−−→(AgNO3)Ag2CO3