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Question

X−−−−(AgNO3)Y (white ppt.)
Y is soluble in nitric acid and ammonia. The ppt. becomes yellowish brown upon addition of excess reagent owing to the formation of Z. If aqueous suspension of Y is boiled then it gives same product Z.

Here Z is:

A
Ag2CO3
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B
Ag
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C
Ag2O
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D
All of these
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Solution

The correct option is C Ag2O
CO23 −−−−(AgNO3)Ag2CO3

Ag2CO3 (Δ)Ag2O +CO2

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