$X - ---- \to (A g N O_{3}) Y$ (white ppt.)
Y is soluble in nitric acid and ammonia. The ppt. becomes yellowish brown upon addition of excess reagent owing to the formation of Z. If aqueous suspension of Y is boiled then it gives same product Z.

Here, X and Y are:

C O_{3}^{2 -}

and

A g_{2} O

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C O_{3}^{2 -}

and

A g_{2} C O_{3}

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H C O_{3}^{-}

and

A g_{2} C O_{3}

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H C O_{3}^{-}

and

A g_{2} O

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Solution

The correct option is B $C O_{3}^{2 -}$ and $A g_{2} C O_{3}$
$C O_{3}^{2 -} - ---- \to (A g N O_{3}) A g_{2} C O_{3}$

$A g_{2} C O_{3} - - \to (Δ) A g_{2} O + C O_{2}$

Suggest Corrections

Similar questions

X - ---- \to (A g N O_{3}) Y

H C O_{3}^{-} (a q .) + O H^{-} (a q .) \to C O_{3}^{2} (a q .) + H_{2} O

An aqueous solution of carbonic acid ( $H_{2} C O_{3}$ ) contains

C O_{2}

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