Question

$X^{+}$, $Y^{2+}$ and $Z^{-}$ are isoelectronic of $C{O}_2$. Increasing order of protons in $X^{+},Y^{2+}$ and $Z^{-}$ is :

• A. $X^{+}=Y^{2+}=Z^{-}$
• B. $X^{+}<Y^{2+}<Z^{-}$
• C. $Z^{-}<X^{+}<Y^{2+}$
• D. $Y^{2+}<X^{+}<Z^{-}$

Answer 1

Answer: (C)

$Z^{-}<X^{+}<Y^{2+}$

$X^{+}$, $Y^{2+}$ and $Z^{-}$ are isoelectronic of $C{O}_2$ means they have 22 electron.
So, $X^{+}$ have 22 electron and 23 proton.
$Y^{2+}$ have 22 electron and 24 proton.
And, $Z^{-}$ have 22 electron and 21 proton.
Therefore, order is $Z^{-}<X^{+}<Y^{2+}$.