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Question

(x+y)3(xy)3 can be factorized as


A

2y(3x2+y2)

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B

2x(3x2+y2)

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C

2y(3y2+x2)

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D

2x(x2+3y2)

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Solution

The correct option is A

2y(3x2+y2)


(x+y)3(xy)3=(x+yx+y)[(x+y)2+(x+y)(xy)+(xy)2]=2y(x2+y2+2xy+x2y2+x2+y22xy)=2y(3x2+y2)


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