(x+y)3−(x−y)3 can be factorized as
2y(3x2+y2)
2x(3x2+y2)
2y(3y2+x2)
2x(x2+3y2)
(x+y)3−(x−y)3=(x+y−x+y)[(x+y)2+(x+y)(x−y)+(x−y)2]=2y(x2+y2+2xy+x2−y2+x2+y2−2xy)=2y(3x2+y2)