The given system of equation is:
x + y = 3 .........(i)
4x − 3y = 26 ........(ii)
On multiplying (i) by 3, we get:
3x + 3y = 9 .......(iii)
On adding (ii) and (iii), we get:
7x = 35
⇒ x = 5
On substituting the value of x = 5 in (i), we get:
5 + y = 3
⇒ y = (3 − 5) = −2
Hence, the solution is x = 5 and y = −2