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Question

X,Y are mid-points of opposite sides AB and DC of a parallelogram ABCD.AY and DX are joined intersecting in P; CX and BY are joined intersecting in Q. What is PXQY?
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A
Rectangle
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B
Rhombus
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C
Parallelogram
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D
Square
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Solution

The correct option is B Parallelogram
ABCD is the given parallelogram

AB=CD ..... (Opposite sides of parallelogram are equal)
So, 12AB=12CD

AX=CY ...... (as X is the mid point of AB and Y is the mid point of CD)
AX||CY ......... (We know AB||CD, as ABCD is the parallelogram)

Quadrilateral AXCY is a prallelogram, as a pair of opposite sides is equal and parallel.

So, XC=YA and XCYA
XQYP ...... (i) (As XQ is part of line XC and YP is part of line YA)
We have ABCD as the given parallelogram
Now, AB=CD ....... (Opposite sides of parallelogram are equal)

So, 12AB=12CD

DY=XB ....... (As X is the midpoint of AB and Y is the mid point of CD)
DYXB ..... (We know ABCD, as ABCD is the parallelogram)

Quadrilateral DXBY is a prallelogram, as a pair of opposite sides is equal and parallel.

So, DX=YB and DX||YB
PX||YQ ...... (ii) (As XP is part of line XD and YQ is part of line YB)

From (i) and (ii) we get,
PXQY is also a parallelogram.

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