$x + y - (z - x - [y + z - (x + y - {z + x - (y + z + x)})])$ is equal to

3 x

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2 y

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x

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0

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Solution

The correct option is C $x$
$x + y - (z - x - [y + z - (x + y - {z + x - (y + z + x)})])$
$= x + y - (z - x - [y + z - (x + y - {z + x - y - z - x})])$
$= x + y - (z - x - [y + z - (x + y - z - x + y + z + x)])$
$= x + y - (z - x - [y + z - x - y + z + x - y - z - x])$
$= x + y - (z - x - y - z + x + y - z - x + y + z + x)$
$= x + y - z + x + y + z - x - y + z + x - y - z - x$
$= x$

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\neq

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