-x-y-x-y-x-2 nbsp- y-2- -x-4 -y-4x-2 -y-4x-4 -y-2

The correct options are A x^4 y^4 C x^4 y^2To simplify : (x+y)(x y)(x^2 nbsp;+ y^2) Using nbsp;the identity, (a + b) (a b) = a^2 b^2 we get, (x+y)( ...

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Byju's Answer

Standard VIII

Mathematics

Finding Squares of Numbers

(x+y)(x-y)(x^...

Question

$(x + y) (x - y) (x^{2} + y^{2}) =$

x^{4} - y^{4}

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x^{2} - y^{4}

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x^{4} - y^{2}

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Solution

The correct options are
A $x^{4} - y^{4}$
C $x^{4} - y^{2}$
$To simplify : (x + y) (x - y) (x^{2} + y^{2})$

Using the identity,
$(a + b) (a - b) = a^{2} - b^{2}$

we get,
$(x + y) (x - y) (x^{2} + y^{2})$
$= (x^{2} - y^{2}) (x^{2} + y^{2})$

Using the same identity again,
$with a = x^{2} and b = y^{2}$ ,
we get,
$(x^{2} - y^{2}) (x^{2} + y^{2})$
$= {(x^{2})}^{2} - {(y^{2})}^{2}$
$= x^{4} - y^{4}$

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Similar questions

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is equal to .

$(x + y) (x - y) (x^{2} + y^{2})$ = ___________.

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(x+y)(x−y)(x2+y2)=

The correct options are A x4−y4 C x4−y2To simplify : (x+y)(x−y)(x2+y2) Using the identity, (a+b)(a−b)=a2−b2 we get, (x+y)(x−y)(x2+y2) =(x2−y2)(x2+y2) Using the same identity again, with a=x2 and b=y2, we get, (x2−y2)(x2+y2) =(x2)2−(y2)2 =x4−y4

$(x + y) (x - y) (x^{2} + y^{2}) =$