$X, Y, Z$ hydrocarbons molecular formula are $C H_{4}, C_{2} H_{4}, C_{2} H_{2}$ . These three are passed through porcelain tube containing ammonical cuprous chloride. The out coming gases would be:

X, Y

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Y, Z

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X, Z

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X, Y, Z

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Solution

The correct option is A X, Y
Out of these three only alkyne reacts with ammonical cuprous chloride and forms red ppt. So outcoming gases will be alkane and alkene i.e $X$ and $Y$ .

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