Question

$X,Y,Z,U$ are four points in a straight line. If distance from $X$ to $Y$ is $15$, $Y$ to $Z$ is $5$, $Z$ to $U$ is $8$ and $X$ to $U$ is $2$, what is the correct sequence of the points?

• A. $X-Y-Z-U$
• B. $X-Z-Y-U$
• C. $X-U-Z-Y$
• D. $X-Z-U-Y$

Answer 1

The correct option is C $X-U-Z-Y$

Given that X,Y,Z and U are four points in a straight line.Such that

$X-Y=15,X-U=2,Z-4=8$ and $Y-Z=5$

$\therefore$ The correct order $\Rightarrow X-U-Z-Y$