Given: x2 – 13x – 30 = 0
On splitting the middle term –13x as –15x + 2x, we get:
x2 – 15x + 2x – 30 = 0
x(x – 15) + 2(x – 15) = 0
(x – 15) (x + 2) = 0
We know that if the product of two numbers is zero, then at least one of them must be zero.
Thus,
x – 15 = 0 or x + 2 = 0
x = 15 or x = 2
Therefore, the solution of the given equation is x = 15, 2.