Question

$x^2-6x+6=0$

Answer 1

$$\begin{gathered} \text{Given:} \\ {x}^2-6x+6=0 \\ \text{Here,} \\ a=1,b=-6\mathrm{and}c=6 \\ \mathrm{Discriminant}D\mathrm{is}\mathrm{given}\mathrm{by}: \\ D=(b^2-4ac) \\ \text{=}{(-6)}^2-4\times 1\times 6 \\ \text{= 36}-24 \\ \text{= 12 > 0} \\ \mathrm{Thus},\text{the roots of the equation are not equal.} \end{gathered}$$