Given: x2 – x – 132 = 0
On splitting the middle term –x as – 12x + 11x, we get:
x2 – 12x + 11x – 132 = 0
x(x – 12) + 11(x – 12) = 0
(x – 12)(x + 11) = 0
We know that if the product of two numbers is zero, then at least one of them must be zero.
Thus,
x – 12 = 0 or x + 11 = 0
x = 12 or x = –11
Therefore, the solution of the given equation is x = 12, –11.