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X2 +Y2 = 2XY ...

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X2 +Y2 = 2XY reaction was studied at a certain temperature . in the beginning 1 mole of X2 was taken in a one litre flask and 2 moles of Y2 was taken in another 2 litre flask .what is the equilibrium concentration of X2 and Y2 ? (given equilibrium conc. of \lbrack XY\rbrack =0.6 mol/l)

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X_{2} + Y_{2} ⇌ 2 X Y

reaction was studied at ,1 certain temperature. In the beginning 1 mole of

X_{2}

, was taken in a one hire flask and 2 moles of

Y_{2}

was taken in another 2 litre flask. What is the equilibrium concentration of

X_{2}

Y_{2}

? (Given equilibrium concentration of [XY] = 0.6

m o l^{- 1}

X_{2} + Y_{2} ⇌ 2 X Y

reaction was studied at a certain temperature. In the beginning

1

X_{2}

was taken in a one litre flask and

2

Y_{2}

was taken in another

2

litre flask. What is the equilibrium concentration of

X_{2}

Y_{2}

, respectively?(Given equilibrium concentration of

[X Y] = 0.6 {m o l}^{- 1}

)

S O_{3}

was placed in a litre reaction flask at a given temperature when the reaction equilibrium was established in the reaction.

2 S O_{3} ⇌ 2 S O_{2} + O_{2}

the vessel was found to contain

0.6

S O_{2}

. The value of the equilibrium constant is :

S O_{3}

was placed in a litre reaction vessel at a certain temperature , the following equilibrium was established,

2 S O_{3} ⇌ 2 S O_{2} + O_{2}

. At equilibrium 0.6 moles of

S O_{2}

were formed. The equilibrium constant of the reaction will be:

4.0

P {C l}_{5}

760 K

2

P {C l}_{5} (g) ⇌ P {C l}_{3} (g) + {C l}_{2} (g)

0.8

{C l}_{2}

was present in the flask. The equilibrium constant would be:

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