Given: x3 y4=1 rArr; 4x 3y = 12 rArr; 3y = 4x 12 rArr; y=43x 123 there4; y=43x 4, which is the required equation of the line. ...

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x3-y4=1

Question

$\frac{x}{3} - \frac{y}{4} = 1$

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Solution

Given: $\frac{x}{3} - \frac{y}{4} = 1$
⇒ 4x $-$ 3y = 12
⇒ 3y = 4x $-$ 12
⇒ $y = \frac{4}{3} x - \frac{12}{3}$
∴ $y = \frac{4}{3} x - 4$ , which is the required equation of the line.

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