The given equations are:
x3+y4=11
⇒ 4x + 3y = 132 ........(i)
and 5x6−y3=−7
⇒ 5x − 2y = −42..........(ii)
On multiplying (i) by 2 and (ii) by 3, we get:
8x + 6y = 264 ........(iii)
15x − 6y = −126 ...........(iv)
On adding (iii) and (iv), we get:
23x = 138
⇒ x = 6
On substituting x = 6 in (i), we get:
24 + 3y = 132
⇒ 3y = (132 − 24) = 108
⇒ y = 36
Hence, the solution is x = 6 and y = 36.