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Byju's Answer
Standard XII
Mathematics
First Fundamental Theorem of Calculus
∫ x 3 x-2 d x
Question
∫
x
3
x
-
2
d
x
Open in App
Solution
∫
x
3
x
-
2
d
x
=
∫
x
3
-
8
+
8
x
-
2
d
x
=
∫
x
3
-
2
3
x
-
2
+
8
x
-
2
d
x
=
∫
x
-
2
x
2
+
2
x
+
4
x
-
2
+
8
x
-
2
d
x
=
∫
x
2
+
2
x
+
4
d
x
+
8
∫
d
x
x
-
2
=
x
3
3
+
2
x
2
2
+
4
x
+
8
ln
x
-
2
+
C
=
x
3
3
+
x
2
+
4
x
+
8
ln
x
-
2
+
C
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14
Similar questions
Q.
If
f
(
x
)
=
∣
∣ ∣ ∣ ∣
∣
2
x
sin
2
(
x
2
)
tan
x
+
x
3
x
+
sin
x
e
x
2
sec
x
2
cos
x
x
4
1
∣
∣ ∣ ∣ ∣
∣
Then value of
π
/
2
∫
−
π
/
2
[
f
(
x
)
+
f
′′
(
x
)
]
2
d
x
=
Q.
If
f
(
x
)
=
∣
∣ ∣ ∣ ∣
∣
2
x
sin
2
(
x
2
)
tan
x
+
x
3
x
+
sin
x
e
x
2
sec
x
2
cos
x
x
4
1
∣
∣ ∣ ∣ ∣
∣
Then value of
π
/
2
∫
−
π
/
2
[
f
(
x
)
+
f
′′
(
x
)
]
2
d
x
=
Q.
f(x) = x
3
(x
-
1)
2
