Question

x⁴ − 2 sin x + 3 cos x

Answer 1

$$\begin{gathered} \frac{d}{dx}\left(x^4-2\sin x+3\cos x\right) \\ =\frac{d}{dx}\left(x^4\right)-2\frac{d}{dx}\left(\sin x\right)+3\frac{d}{dx}\left(\cos x\right) \\ =4x^4-2\cos x-3\sin x \end{gathered}$$