X2-b2xb-2xc-a2-xa- xb- x74-x- solve for x

(xa+b)2 (xb+c)2 (xc+a)2 ÷ (xa.xb.xc)4 = x. = gt;(x2a+2b)(x2b+2c) (x2c+2a) ÷ (x4a.x4b.x4c) = x = gt;(x2a+2b+2b+2c+2c+2a )÷ (x4a+4b+4c) = x = gt;(x4a+ ...

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Byju's Answer

Standard VIII

Mathematics

Inequalities of Negative Numbers Using Everyday Life Situations

x2+b2xb+2xc+a...

Question

(x^a+b)² (x^b+c)² (x^c+a)² ÷ (x^a.x^b.x^c)⁴= x. Solve for x.

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Solution

(x^a+b)² (x^b+c)² (x^c+a)² ÷ (x^a.x^b.x^c)⁴= x.
=>(x^2a+2b)(x^2b+2c) (x^2c+2a) ÷ (x^4a.x^4b.x^4c)= x
=>(x^{2a+2b+2b+2c+2c+2a} )÷ (x^4a+4b+4c)= x
=>(x^4a+4b+4c )÷ (x^4a+4b+4c)= x
=>1=x
=>x=1

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(xa+b)2 (xb+c)2 (xc+a)2 ÷ (xa.xb.xc)4 = x. Solve for x.

(xa+b)2 (xb+c)2 (xc+a)2 ÷ (xa.xb.xc)4 = x. =>(x2a+2b)(x2b+2c) (x2c+2a) ÷ (x4a.x4b.x4c) = x =>(x2a+2b+2b+2c+2c+2a )÷ (x4a+4b+4c) = x =>(x4a+4b+4c )÷ (x4a+4b+4c) = x =>1=x =>x=1

(x^a+b)² (x^b+c)² (x^c+a)² ÷ (x^a.x^b.x^c)⁴= x. Solve for x.

(x^a+b)² (x^b+c)² (x^c+a)² ÷ (x^a.x^b.x^c)⁴= x.
=>(x^2a+2b)(x^2b+2c) (x^2c+2a) ÷ (x^4a.x^4b.x^4c)= x
=>(x^{2a+2b+2b+2c+2c+2a} )÷ (x^4a+4b+4c)= x
=>(x^4a+4b+4c )÷ (x^4a+4b+4c)= x
=>1=x
=>x=1