Question

$xA+yB\to zC.If-\frac{d\left[A\right]}{dt}=-\frac{d\left[B\right]}{dt}=1.5\frac{d\left[C\right]}{dt}$ then x.y and z are

• A. 1, 1, 1
• B. 3, 2, 3
• C. 3, 3, 2
• D. 2, 2, 3

Answer 1

The correct option is C 3, 3, 2

$\frac{d\left[A\right]}{dt}=\frac{-d\left[B\right]}{dt}=\frac{3}{2}\frac{d\left[C\right]}{dt}\frac{-1}{3}\frac{d\left[A\right]}{dt}=\frac{-1}{3}\frac{d\left[B\right]}{dt}=\frac{1}{2}\frac{d\left[C\right]}{dt}$
x =3
y = 3
z = 2