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Question

xA+yBzC.Ifd[A]dt=d[B]dt=1.5d[C]dt then x.y and z are

A
1, 1, 1
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B
3, 2, 3
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C
3, 3, 2
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D
2, 2, 3
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Solution

The correct option is C 3, 3, 2
d[A]dt=d[B]dt=32d[C]dt13d[A]dt=13d[B]dt=12d[C]dt
x =3
y = 3
z = 2

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