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Byju's Answer
Standard X
Chemistry
Cationic Radius
xample, anZn,...
Question
xample, anZn, 4s and 3d e experience different effective nuclear charge4s, σ 10 x 1.0 + 18 x 0.85 + 1 x 0.35 25.65For eZ 30-25.65 4.353d, σ-181.0 + 9 x 0.35-21.15Z 30-21.15 8.85
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Q.
Find
x
and
y
in the given figure.
Q.
0.5
(
x
−
0.4
)
0.35
−
0.6
(
x
−
2.71
)
0.42
=
x
+
61
Q.
As per Pauling, the radius of an isoelectronic ion in a given crystal is inversely proportional to the effective nuclear charge,
Z
∗
.
Z
∗
=
Z
−
σ
; where
σ
represents the screening constant. The crystal structure of
NaF
is shown as below :
The radius of
F
−
in pm is
(
130
+
x
)
. The value of
x
in nearest possible integer is
Q.
Match the following :
List I
1. Correlation in Bivariable Frequency table.
2. Probable error and co-efficient correlation.
3. Rank correlation.
4. Karl pearson's co-efficient of correlation.
List II
a)
Σ
f
d
x
d
y
−
Σ
f
d
x
Σ
f
d
y
N
√
Σ
f
d
x
2
−
(
Σ
f
d
x
)
2
N
√
Σ
f
d
y
2
−
(
Σ
f
d
y
)
2
N
b)
r
=
0.6745
−
r
2
√
N
c)
r
=
1
−
6
Σ
d
2
n
(
n
2
−
1
)
d)
r
=
Σ
x
y
N
σ
x
σ
y
Codes :
1 2 3 4
Q.
The formula for an effective nuclear charge is:
(if
σ
is screening constant)
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