$\int (x^{e} + e^{x} + e^{e}) d x$

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Solution

$\int (x^{e} + e^{x} + e^{e}) d x = \int x^{e} d x + \int e^{x} d x + e^{e} \int 1 d x = \frac{x^{e + 1}}{e + 1} + e^{x} + x \cdot e^{e} + C$

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