Question

$Xe{F}_2$ reacts with $P{F}_5$ to give:

• A. $Xe{F}_6$
• B. $\left[XeF{]}^{+}\right[P{F}_6{]}^{-}$
• C. $Xe{F}_4$
• D. $\left[P{F}_4{]}^{+}\right[Xe{F}_3{]}^{-}$

Answer 1

Answer: (B)

$\left[XeF{]}^{+}\right[P{F}_6{]}^{-}$

$P{F}_5$ is a fluoride ion acceptor so it yields cationic species with xenon fluorides.

$\left[Xe{F}_2\right]+\left[P{F}_5\right]\to \left[XeF{]}^{+}\right[P{F}_6{]}^{-}$

So, the correct answer is $B$