XeF 2 reacts with SbF 5 to form-A- - XeF - SbF 6-B- - XeSbF 6-C- - XeF 4-D- - XeF 3- SbF 4-

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Wurtz Halide Reaction

XeF 2 reacts ...

Question

$X e F_{2}$ reacts with $S b F_{5}$ to form:

[X e F] [S b F_{6}]

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[X e F_{3}] [S b F_{4}]

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[X e S b F_{6}]

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[X e F_{4}]

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Solution

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Similar questions

X e F_{4}

S b F_{5}

S b F_{5}

X e F_{4}

X e F_{6}

[X e F_{3}^{+}] [{S b F_{6}}^{-}]

[X e F_{5}^{+}] [{S b F_{6}}^{-}]

X e F_{3}^{+}

[X e F_{5}^{+}]

S b F_{5}

X e F_{4}

X e F_{6}

[X e F_{3}^{+}] [S b F_{6}]^{-} a n d [X e F_{5}^{+}] [S b F_{6}^{-}] .

X e F_{3}^{+}

X e F_{5}^{+}

S b F_{5}

X e F_{4}

X e F_{4} + S b F_{5} \to

C I F + H_{2} O ⟶

X e F_{4} + H_{2} O ⟶

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