$X e F_{4}$ disproportionate in aqueous solution to $X e (0)$ and $X e (V I) . X e (V I)$ is formed from which oxidation state?

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Solution

The correct option is B 4
$X e F_{4}$ disproportionates in aqueous solution to Xe(0) and $X e (V I) . X e (V I)$ is formed from +4 oxidation state, as in reactant $X e F_{4}$ , oxidation state is +4.

$X e F_{4} + 3 H_{2} O \to X e + X e O_{3} + 3 H_{2} F_{2} + F_{2}$

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