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Fluorides of Xenon

" XeF4 dispr...

Question

" $X e F_{4}$ disproportionates to stable $X e O$ and $X e O_{4}$ ."
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Solution

$X e F_{4}$ disproportionates in water to give unstable $X e O$ and $X e O_{4}$ . $X e O$ further changes to $X e$ and $X e O_{4}$ further changes to $X e O_{3}$ .
Hence, the overall reaction is as follows:
$6 X e F_{4} + 12 H_{2} O \to 2 X e O_{3} + 4 X e + 3 O_{2} + 24 H F$
Therefore, $X e F_{4}$ disproportionates to give stable $X e$ and $X e O_{3}$ .

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