$X e F_{6}$ exists as $(R b)^{+} [X e F_{7}]^{-}$ in $R b F$ .

True

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False

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Solution

The correct option is A True
Xenon hexafluoride acts as a Lewis acid, binding one fluoride ion. Thus, it can form a salt with rubidium fluoride to give rubidium heptafluoroxenonate.
$X e F_{6} + F^{-} \to X e F_{7}^{-}$ (Lewis acid)
$X e F_{6} + R b F \to (R b)^{+} [X e F_{7}]^{-}$

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